Arithmetic Progressions
If you
have the sequence 2, 8, 14, 20, 26, then each term is 6 more than the previous
term. This is an example of an arithmetic progression (AP) and
the constant value that defines the difference between any two consecutive
terms is called the common difference.
If an
arithmetic difference has a first term a and a common
difference of d, then we can write
a, (a +
d), (a + 2d),... {a + (n-1) d}
where the nth term
= a + (n−1)d
Sum of
Arithmetic series
The sum
of an arithmetic series of n terms is found by making n/2
pairs each with the value of the sum of the first and last term. (Try
this with the sum of the first 10 integers, by making 5 pairs of 11.)
This
gives us the formula:
where a =
first term and l = last term.
As the
last term is the nth term = a + (n − 1)d we can rewrite this as:
(Use the
first formula if you know the first and last terms; use the second if you know
the first term and the common difference.)
Geometric
Progressions
If you
have a sequence such as: 81, 27, 9, 3, 1, 1/3, 1/9,... then
each term is one third of the term before.
This can
be written as 81, 81(1/3), 81(1/3)2, 81(1/3)3, 81(1/3)4,...
It is an
example of a Geometric Progression (GP) where the each term is
a multiple of the previous one. The multiplying factor is called the common
ratio.
So a GP
with a first term a and a common ratio r with n terms,
can be stated as
a, ar, ar2, ar3, ar4...arn-1 , where
the nth term = arn-1
Example:
In the
sequence, 400, 200, 100, 50,... find the 8th term.
a = 400,
r = 0.5 and so the 8th term = 400 × 0.57 =
3.125
Note: To
find which term has a certain value you will need to use logarithms.
Example:
In the
sequence, 2, 6, 18, 54 ... which is the first term to exceed 1,000,000?
a = 2, r
= 3.
2 × 3n-1 >
1,000,000
3n-1 >
500000
(n − 1)
log 3 > log 500000
n > 12.94
Therefore:
n = 13
Example:
In the
earlier sequence, 400, 200, 100, 50 ... which is the first term that is less
than 1?
400 × 0.5(n-1] <
1
0.5(n-1) <
0.0025
(n-1) log
0.5 < log 0.0025
Therefore:
n > 9,
or n = 10
Note: The
inequality sign changed because we divided by a negative (log 0.5 < 0)
Sum of
Geometric series
The sum
of the terms can be written in two ways.
where a =
first term, r = common ratio and r ≠ 1.
(use this
formula when r < 1).
Example:
Evaluate,
(Note: there
are 9 terms.)
The first
term is when n = 2
(i.e 2.362 =
5.5696)
Using the
formula for the sum of a geometric progression gives:
which is
approximately 9300 (to 3 s.f.).
Convergence
The sum
of an infinite series exists if:
-1 < r
< 1 or | r | < 1
This is
because each successive term is getting smaller and so the series will tend
towards a certain limit. This limit is found using the second of our two formula:
If | r |
< 1 then as n → ∞, rn → 0
and so:
Example:
the
series 1/3 + (1/3)2 + (1/3)3 + (1/3)4 +
... converges and its sum is 1 as n approaches ∞.
(A
sequence such as n3 has the first 6 terms as 1 + 8 + 27 + 64 + 125 + 216. As n
approaches infinity, the sum also increases. Therefore, it is not convergent.
This series is divergent.
Every AP
has a sum that approaches infinity as n increases, so every AP is divergent.)
Example
Find 1 -
1/2 + 1/4 - 1/8 + ...
1 - 1/2 +
1/4 - 1/8 + ... = 1 + (-1/2) + (-1/2)2 +
(-1/2)3 + ...
This is a
geometric progression where r = -½, so | r | < 1.
Therefore
this series converges to:
Two final
pieces of information that may be useful:
Arithmetic
mean
The arithmetic
mean of two numbers m and n is given by:
Arithmetic
mean = ½(m+n)
This is
the way of finding a missing term in between two known terms.
Example:
The 4th term
of an AP is 14, the 6th term is 22. The 5th term
will be the Arithmetic Mean of these two values.
i.e. (14
+ 22)/2 = 18 (here d = 4 and a = 2).
Geometric
mean
The geometric
mean of two numbers m and n is given by:
Geometric
mean = √(mn)
This
represents the value between two others in a GP.
Example:
The 7th term
of a GP is 6, the 9th is 1.5. The 8th term
is:
√(6×1.5)
= √9 = 3
Here r =
0.5 and a = 384.
Reference:
http://www.s-cool.co.uk/a-level/maths/sequences-and-series/revise-it/arithmetic-and-geometric-progressions 










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